Interview Questions On Alternator

Hello Engineers.

Today we are sharing alternator interview questions with answer.

Q. 1. What are the two types of turbo-alternators ?
Ans.  Vertical and horizontal.

Q. 2. How do you compare the two ?
Ans. Vertical type requires less floor space and while step bearing is necessary to carry the weight of the moving element, there is very little friction in the main bearings. The horizontal type requires no step bearing, but occupies more space.

Q. 3. What is step bearing ?
Ans. It consists of two cylindrical cast iron plates which bear upon each other and have a central recess between them. Suitable oil is pumped into this recess under considerable pressure.

Q. 4. What is direct-connected alternator ?
Ans. One in which the alternator and engine are directly connected. In other words, there is no intermediate gearing such as belt, chain etc. between the driving engine and alternator.

Q. 5. What is the difference between direct-connected and direct-coupled units ?
Ans. In the former, alternator and driving engine are directly and permanently connected. In the latter case, engine and alternator are each complete in itself and are connected by some device such as friction clutch, jaw clutch or shaft coupling.

Q. 6. Can a d.c. generator be converted into an alternator ? If yes then how ?
Ans. Yes. A DC generator can be converted into an alternator. By providing two collector rings on one end of the armature and connecting these two rings to two points in the armature winding 180° apart.

Q. 8. Would this arrangement result in a desirable alternator ?
Ans. No

Q. 9. How is a direct-connected exciter arranged in an alternator ?
Ans. The armature of the exciter is mounted on the shaft of the alternator close to the spider hub. In some cases, it is mounted at a distance sufficient to permit a pedestal and bearing to be placed between the exciter and the hub.

Q. 10. Any advantage of a direct-connected exciter ?
Ans. Yes, economy of space.

Searches related to Basic MCQ Interview Questions On Alternator

electrical machines objective questions and answers pdf

electrical machines objective questions pdf download

mcq on alternator with answers

power factor of alternator at no load

objective questions on synchronous machines pdf

open wire test is used for?

synchronous machines questions and answers

synchronous machines objective questions with answers

Q. 11. Any disadvantage ?
Ans. The exciter has to run at the same speed as the alternator which is slower than desirable. Hence, it must be larger for a given output than the gear-driven type, because it can be run at high speed and so made proportionately smaller.

Objective Types Questions Of High Voltage Engineering Part 2

Q.1 A generating voltmeter is used to measure
A. Impulse voltage
B. AC voltage
C. dc voltage
D. All
Answer : c

Q.2 A series capacitance voltmeter can measure
A. DC voltage
B. Rms value voltage
C. Ac voltage
D. All
Answer : c

Must Read: Transformer Interview Questions

Q.3 cvt when tunned does not have
A. Ratio error
B. Phase angle error
C. Both a and b
D. None
Answer : b

Q.4 Electrostatic voltmeter can measure
A. Dc voltmeter
B. Ac voltmeter
C. Both a and b
D. None
Answer c

Q.5 sphere gaps are used to measure
A. Dc voltage
B. Ac voltage
C. Impulse voltage
D. All
Answer d

Q.6 hall generators are normally used to measure
A. Impulse voltage
B. Unidirectional impulse current
C. Any type of impulse voltage
D. All
Answer b

Q.7 for measuring high impulse currents, the best type of shunt is
A. Squirrel cage
B. Bifilar strip
C. Disc
D. Coaxial tubular
Answer d

Don't Miss : Alternator Interview Questions

Q.8 to measure a high voltage of peak value about 150kv, the suitable
sphere gap would be
A. 5cm
B. 10cm
C. 15 or 25 cm
D. 50 cm
Answer c
Q.9 cockcroft walton circuit is used for
A. Dc voltage generation
B. Ac voltage generation
C. Both a and b
D. None
Answer a
Q. 10 cascaded transformer is used for
A. Dc voltage generation
B. Ac voltage generation
C. Both a and b
D. None
Answer b

High voltage engineering objective interview questions part 1

1. Electrical conduction in gases was first studied in
A. Loeb
B. Maxwell
C. Townsend
D. None

Answer : c
Q.2 SF6 is a
A. Natural gas
B. Electronegative gas
C. Ionize gas
D. Non attaching gas
Ans : b

Must Read: Electrical Engineering Interview Questions

Q.3 Minimum sparking potential of air is
A. 40 v
B. 100 v
C. 4.4v
D. 325v
Answer : d

Q.4 The requirement of gases for insulation purpose is
A. High dielectric strength and thermal stability
B. High thermal stability
C. High dielectric strength only
D. None
Answer : A

Q.5 Transformer oil is
A. Askeral
B. Silicone oil
C. Polyster oil
D. Mineral oil
Answer: D

Q.6 The breakdown strength of mineral oil is about
A. 20kv/mm
B. 30-40 kv/mm
C. 50 kv/mm
D. None
Answer : B

Q.7 Dielectric constant of mineral oil is
A. 1.5 to 2.0
B. 2.2 to 2.4
C. 3.0 to 3.5
D. None
Answer : b

Q.8 maximum dielectric strength obtained with pureliquid
A. 100 kv/mm
B. 10 kv/mm
C. 1mv/mm
D. All
Answer :a

Q.9 which liquid has highest breakdown strength is
A. Mineral oil
B. Silicone oil
C. Polyolefins
D. None
Answer : b
Q. 10 conduction and breakdown in commercial liquids is affected by
A. Solid partical
B. Vapour
C. Electrode materials
D. All
Answer : d

If you face any problem with any question then comment below.

Electronics Engineering Projects On Doorbell Circuit

The electronic doorbell in this article is the most simplest among the advance projects in this website. There are many other benefits of the project doorbell. The circuit for the electronic doorbell here will help realise whether the visitor is in front door or in back door. More about there is two LED indicatorwith different colours which provide visual indication to check if anyone had come nor not in your absence.

PART LIST

Transistors

T1,T2,T5	BC148B
T3,T4	BC158B
T6	AC128

Diodes

D1,D2,D3,D4	1N4001
D5	GREEN LED
D6	RED LED

Capacitors

C1,C2,C3

0.01 μF

Resistors

R1,R7,R8.R9,R10	2.2 KΩ
R2	47Ω
R3,R4	100KΩ
R5,R6	10KΩ
R11,R12	330Ω

Miscellaneous

S1	ON/OFF toggle switch for memory
S2,S3	Switch for doorbell
BATT	9-Volt Battery
LS	Loud Speaker 8Ω
OTHERS	PCB , Connecting Wires, Hardware,enclosure etc

Circuit Description

Working Principal

The presented circuit of doorbell in this site is employs a direct couple complementary amplifier and two regenerative latches. The working principal of the circuit doorbell is simple. There are two switches S2 and S3 for FRONT and REAR door respectively. The S1 is open the circuit act as a two-way doorbell. In this case circuit act as a two-way doorbell  with memory, that is the audio alarm indicates whether the visitor is calling from the front door or from back door. 

 When the S2 is pressed , diode D1 conducts and the complementary amplifier built around transistors T5 and T6 . Now T5 and T6 starts oscillating due to the positive feedback via capacitor C1. In this case low frequency tone is produced which indicates that visitor is a calling form front door. Similarly when switch S3 is pressed then D2 conducts and a high frequency tone is produced to indicate the visitor is calling at the rear door.

In your absence in someone come to your home and call you then it will recorded in its memory. The circuit can provide you an indication on return whether someone had come to your house and called from front door or rear door.To use the memory unit of this circuit you have to switch on the S1 which is the switch for memory. After that whenever someone call you from front door or rear door it will be indicated by the corresponding colour LED to the door. The corresponding LED will be light up and remains in that state until you return to your home. The Circuit can be reset by switching off the memory switch S1.

 When switch S1 in keep ON. This case if someone come to your home and press the switch of front door that is S2 then diode D3 conducts through diode D5 and positive pulse is applied to the base of the transistor T2. After that the regenerative pair built around transistor T2 and T4 quickly full conduction and RED LED  that is D6 lights up and remains  in that state until switch S1 is switch OFF. In the same way when someone press the switch of rear door that is S3 diode D4 conducts through resistor R6 and a positive pulse is applied to the base of the transistor T1 then the regenerative pair comprising transistor T1 and T3 suddenly goes into full saturation and the D5 that is GREEN LED lights up and remains in that stat until the memory switch S1 in switched OFF. 

If both the LEDs are found glowing on returning from a visit then you may be surmise that the visitor(s) called yo at the both the doors. In this circuit, diode D1 and D2 are necessary to isolate the front switch S2 and the rear switch S3. In same way D3 and D4 are used to isolate the audio section of this circuit from regenerative latches. C2 and C3 are used to avoid false triggering of the regenerative latches by the surge produced when S1 is switched ON, as this is generally caused due to high gain of the transistors.